The distance between the adjacent atomic planes in CaCO3 is 0.3nm. The smallest Bragg scattering for 0.03nm X-ray is?
The distance between the adjacent atomic planes in CaCO3 is 0.3nm. The smallest Bragg scattering for 0.03nm X-ray is?
Explanation
To find the smallest Bragg scattering angle, we can use Bragg's law:
2d sin(θ) = nλ
where d is the distance between the atomic planes, θ is the scattering angle, n is an integer (which is 1 for the smallest angle), and λ is the wavelength of the X-ray.
Given:
d = 0.3 nm
λ = 0.03 nm
Rearranging Bragg's law to solve for θ, we get:
sin(θ) = λ / (2d)
= 0.03 nm / (2 × 0.3 nm)
= 0.05
θ = arcsin(0.05)
≈ 2.9°