A torque of 2 x 10^-4 Nm is applied to produce an angular acceleration of 4rad/s^2 in a rotating body. What is the moment of inertia of the body?

0.5 × 10^-4 kgm^2

0.5 kgm^2

0.5 × 10^4 kgm^2

None of these

To find the moment of inertia (I) of the rotating body, we can use the formula:

τ = I × α

where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

Given:

τ = 2 × 10^-4 Nm

α = 4 rad/s^2

Rearranging the formula to solve for I:

I = τ / α

= (2 × 10^-4 Nm) / (4 rad/s^2)

= 0.5 × 10^-4 kgm^2