A cubical block rests on an incline plane of μ = 1/√3. Determine the angle of inclination when the block just slides down the inclined plane?

50°

30°

40°

None of these

Since μ = 1/√3, we can use the fact that μ = tan(θ) when the block just slides down the inclined plane.

μ = 1/√3 = tan(θ)

θ = arctan(1/√3)

θ = 30°