The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum planet will be (if it is a second's pendulum on earth)?
کسی سیارے کے بڑے پیمانے پر اور قطر زمین سے دوگنا ہوتا ہے۔ پینڈولم سیارے کے دوچار ہونے کی مدت ہوگی (اگر یہ زمین پر دوسرا لاکٹ ہے)؟
Answer: 2√2 seconds
Explanation
- The formula for the period of a pendulum is T = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity.
- Since the mass and diameter are doubled, the acceleration due to gravity (g) on the planet will be half that of Earth.
- Therefore, the new period of oscillation will be √2 times the period on Earth, meaning if it was a second's pendulum on Earth, it will be 2√2 seconds on the planet.
This question appeared in
Past Papers (4 times)
Lecturer Physics Past Papers and Syllabus (1 times)
SPSC 25 Years Past Papers Subject Wise (Solved) (2 times)
SPSC Past Papers (1 times)
This question appeared in
Subjects (1 times)
EVERYDAY SCIENCE (1 times)
Related MCQs
- Which planet rotates so slowly (slowest rotating planet) on its axis that its one day is almost equal to one year of the earth?
- If the mass of the bob of a simple pendulum increases its time period will
- Where is the slowest pendulum vibration observed on Earth?
- Escape velocity on Earth is 11.2 km/s. What would be the escape velocity on a planet whose mass is 1000 times and radius is 10 times that of Earth?
- The nearest planet to the Earth is ______?
- Which planet has similar size as Earth?
- Which planet which is easily visible from the Earth?
- Which planet is called the Sister of the Earth?
- Which planet revolves clockwise around Sun from Earth?
- About 78% of the planet Earth is composed of ________ rocks.