The power loss P in a resistor is calculated using the formula P = V²/R. The uncertainty in the potential difference V is e% and the uncertainty in R is 2%. What is the uncertainty in P?

11%

None of these

Uncertainty propagation in multiplication/division follows the rule:
$\frac{Δ P}{P} = 2 \times \frac{Δ V}{V} + \frac{Δ R}{R}$

Given uncertainty in V = e% and uncertainty in R = 2%,
$text{Total uncertainty} = 2(e) + 2 = 8%$ (assuming e = 3%)