When object is thrown upward it rises to height "h" how high is the object in terms of h, when it has lost one third of its original Kinetic Energy?

h/4

h/3

h/2

None of these

The total mechanical energy (kinetic + potential) remains constant.

Initially, the object has total energy E = K + U = mgh.

When it loses 1/3 of its kinetic energy, the remaining kinetic energy is 2/3 of the initial value.

Using energy conservation, solving for height gives h/2.