A 20-F capacitor is charged to 200V. It's stored energy is _______?
A 20-F capacitor is charged to 200V. It's stored energy is _______?
Explanation
To find the stored energy, we can use the formula:
Energy (E) = 0.5 × Capacitance (C) × Voltage² (V²)
Given:
C = 20 F
V = 200 V
E = 0.5 × 20 F × (200 V)²
= 0.5 × 20 × 40,000
= 400,000 J