A 20-F capacitor is charged to 200V. It's stored energy is _______?

A 20-F capacitor is charged to 200V. It's stored energy is _______?

Explanation

To find the stored energy, we can use the formula:

Energy (E) = 0.5 × Capacitance (C) × Voltage² (V²)

Given:

C = 20 F

V = 200 V

E = 0.5 × 20 F × (200 V)²

= 0.5 × 20 × 40,000

= 400,000 J