A resistor of 4kΩ with tolerance 10% is connected in parallel with a resistor of 6 kΩ with tolerance 10%. The tolerance of the parallel combination is nearly ______?

40%

10%

20%

None of these

The equivalent resistance (R_eq) of the parallel combination:

R_eq = (4 kΩ × 6 kΩ) / (4 kΩ + 6 kΩ) = 2.4 kΩ

The tolerance calculation:

Since both resistors have the same relative tolerance (10%), the resultant parallel combination will also have a tolerance close to 10%.