What will happen to orbital speed of a satellite if its orbital radius (R+h) is half of its initial value?

Increase √2 times

Decrease √2 times

Increase 2 times

None of these

The orbital speed (v) of a satellite is given by:

v = √(GM / (R + h))

If the orbital radius (R + h) is halved:

v' = √(GM / ((R + h) / 2))

= √(2GM / (R + h))

= √2 * √(GM / (R + h))

= √2 * v

So, the orbital speed will increase √2 times.