What is the magnetic field strength at a distance of 2 cm from a wire carrying a current of 5 A?

Answer: 5 × 10⁻⁵ T

$B = μ _{0} I/$ 2πr

Where:

$B = frac{4pi times 10^{-7} , text{T·m/A} times 5 , text{A}}{2 times 3.14 times 0.02, text{m}}$ 2×3.14×0.02m

Let’s calculate step by step:

Numerator:

$4pi times 10^{-7} times 5 = 20pi times 10^{-7}$

Denominator:

$2 times 3.14 times 0.02 = 0.1256$

Now,

$B = frac{20pi times 10^{-7}}{0.1256}$ 0.1256

$approx frac{62.8 times 10^{-7}}{0.1256} approx 5 times 10^{-5} , text{T}$ 0.1256 ≈5×10^−5T

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