A small flashlight bulb draws 300 mA from its 1.5 V battery. What is the resistance of the bulb?

6 Ω

5 Ω

4 Ω

None of these

Step 1: Recall Ohm's Law

V = IR, where V is voltage, I is current, and R is resistance.

Step 2: Convert current to amperes

300 mA = 0.3$ A

Step 3: Calculate the resistance

R = V/I = 1.5/0.3 = 5 Ω