Consider a projectile thrown initially at a speed of 20 m/s at an angle of 76° from horizontal. When it reaches the highest point of its trajectory, angle between its velocity and acceleration is
Consider a projectile thrown initially at a speed of 20 m/s at an angle of 76° from horizontal. When it reaches the highest point of its trajectory, angle between its velocity and acceleration is
Explanation
At the highest point of a projectile's motion:
- Its velocity is purely horizontal (vertical component = 0).
- Its acceleration is still vertically downward due to gravity.
So, the velocity vector is horizontal, and the acceleration vector is vertical ⇒ they are perpendicular.
∴ Angle between velocity and acceleration = 90°