Amount of NaOH required to prepare 250 cm³ of 1 M solution is?

10 g

6 g

2 g

4 g

To prepare 250 cm³ (or 250 mL) of a 1 M NaOH solution, you need 10 grams of NaOH.

This is because the molar mass of NaOH is 40 g/mol, and a 1 M solution contains 1 mole of solute per liter of solution.

Therefore, 250 mL (0.25 L) of a 1 M solution would require 0.25 moles of NaOH, which translates to 10 grams (0.25 moles * 40 g/mol).