Molarity of a solution which is prepared by dissolving 40g sodium chloride in 500cm^3 of solution is?

1.4M

1.33M

1.5M

To calculate the molarity, we need to calculate the number of moles of sodium chloride (NaCl) dissolved in 500 cm³ (or 0.5 L) of solution.

Molar mass of NaCl = 58.44 g/mol

Number of moles = mass / molar mass = 40 g / 58.44 g/mol ≈ 0.684 mol

Molarity = number of moles / volume (in liters) = 0.684 mol / 0.5 L ≈ 1.368 M

Rounded to one decimal place, this is approximately 1.4M.