Molarity of a solution which is prepared by dissolving 40g sodium chloride in 500cm^3 of solution is?
Answer: 1.4M
Explanation
To calculate the molarity, we need to calculate the number of moles of sodium chloride (NaCl) dissolved in 500 cm³ (or 0.5 L) of solution.
Molar mass of NaCl = 58.44 g/mol
Number of moles = mass / molar mass = 40 g / 58.44 g/mol ≈ 0.684 mol
Molarity = number of moles / volume (in liters) = 0.684 mol / 0.5 L ≈ 1.368 M
Rounded to one decimal place, this is approximately 1.4M.
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Subjects (4 times)
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GENERAL SCIENCE (2 times)
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