When the angle of refraction is 90° and the refractive index for water is 1. 33, the critical angle is ______?
Answer: 48.8°
Explanation
The critical angle is the angle of incidence above which total internal reflection occurs.
It can be calculated using Snell's law:
n1 sin(θ1) = n2 sin(θ2)
where n1 = 1.33 (refractive index of water), θ1 = critical angle, n2 = 1 (refractive index of air), and θ2 = 90° (angle of refraction).
Rearranging the equation to solve for θ1, we get:
θ1 = arcsin(n2 / n1)
Substituting the values, we get:
θ1 = arcsin(1 / 1.33) ≈ 48.8°
So, the critical angle is approximately 48.8°.
This question appeared in
Subjects (4 times)
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