The magnitude of force between two unit positive charges when the distance between them is 1m would be?

The magnitude of force between two unit positive charges when the distance between them is 1m would be?

Explanation

The magnitude of the force between two unit positive charges (each with a charge of 1 Coulomb) separated by a distance of 1 meter in a vacuum is given by Coulomb's Law:

F = k × (q1 × q2) / r^2

where:

F = force (in Newtons)

k = Coulomb's constant (approximately 8.98755 × 10^9 N m^2 C^2)

q1 and q2 are the charges (in Coulombs)

r is the distance between the charges (in meters)

Plugging in the values, we get:

F ≈ (8.98755 × 10^9 N m^2 C^2) × (1 C × 1 C) / (1 m)^2

F ≈ 8.98755 × 10^9 N

F ≈ 9 × 10^9 N (approximately)

Since 1 Newton is equal to 10^9 N (by definition), we can simplify the answer to:

F ≈ 1 N (approximately)