Find the missing number in the series below (i) 1, 8, 4, 27, 9, ? (ii) 3,6,8,16,18,? (iii) 2, 8, 512, ? (iv) 81 ,9,64 ,8,?,12 (v) 6, 11, 21, 36, 56, ?

Find the missing number in the series below (i) 1, 8, 4, 27, 9, ? (ii) 3,6,8,16,18,? (iii) 2, 8, 512, ? (iv) 81 ,9,64 ,8,?,12 (v) 6, 11, 21, 36, 56, ?

Explanation
Nont:Quetsion contain 5 parts each parts contain 5 marks and total marks of the whole question is 20

(i) 1, 8, 4, 27, 9,?

This series alternates between cubes and squares:


  • 1 = 1^3
  • Next:

Missing number: 64


(ii) 3, 6, 8, 16, 18, ?

This series appears to follow a pattern:

  • First,
    3 to 6
    (adding 3)
  • Then,
    6 to 8
    (adding 2)
  • Next,
    8 to 16
    (doubling)
  • Then, (adding 2)
  • The next step likely doubles:
    18 times 2 = 36

Missing number: 36


(iii) 2, 8, 512, ?

This sequence involves raising the number to an increasing power of 3:

  • Cube Series
  • 2 x 2 x 2 = 8  (2^3=8)
  • 8 x 8 x 8 = 512 (8^3 = 512)
  • 512 x 512 x 512 = 134217728


(iv) 81, 9, 64, 8, ?, 12

This pattern alternates between division and taking the square root:


  • 64 div 8 = 8
  • Next: 144=12

(v) 6, 11, 21, 36, 56, ?

Addition of Multiples of 5

6+5 =11

11 + 10 = 21

21 + 15 = 36

36 + 20 = 56

56 + 25 = 81