A ball is thrown with a speed of 36 m/s and is caught at the same height. What is the total horizontal distance it covered?
Answer: 132.24 m
Explanation
Let's assume the ball is thrown at an angle of 45° for maximum range.
Range = (u² * sin(2θ)) / g
Here, u = 36 m/s, θ = 45°, g = 9.8 m/s²
Range = (36² * sin(90°)) / 9.8
= (1296 * 1) / 9.8
= 1296 / 9.8
≈ 132.24 m
This question appeared in
Past Papers (3 times)
NTS Past Papers (1 times)
Punjab Masstransit Authority PMA Past Papers and Syllabus (2 times)
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