At 3:00 AM, the temperature was 13°C below zero, but by noon it had risen to 32°C. Therefore, the average hourly increase in temperature was ______?
Answer: 5°C
Explanation
Initial temperature = -13°C
Final temperature = 32°C
Total temperature rise = 32 - (-13)
= 32 + 13
= 45°C
Time elapsed = 9 hours (from 3:00 AM to noon)
Average hourly increase = Total temperature rise / Time elapsed
= 45°C / 9 hours
= 5°C/hour
This question appeared in
Past Papers (5 times)
PPSC 5 Years Past Papers Subject Wise (Solved with Details) (2 times)
PPSC Past Papers (1 times)
PPSC PHP ASI Past Papers and Syllabus (1 times)
PPSC Punjab Police ASI Past Papers and Syllabus (1 times)
This question appeared in
Subjects (1 times)
MATHS MCQS (1 times)
Related MCQs
- The Increase in average temperature of the earth is called global warming. How many degree(s) global temperature has increased in the last 100 years?
- The temperature measured in Murree at noon was 16.6°C. At midnight temperature was 20.4°C lower. What was the temperature at midnight?
- Hourly temperature recorded by weather bureau is the example of ?
- Rate of reaction will increase when temperature ______?
- With the increase in pond water temperature the dissolved oxygen concentration will ______?
- The average temperature for human ______ centigrade.
- The average temperature on Monday, Tuesday, and Wednesday was 41°C. If the temperature on Monday was 40°C, and the temperature on Tuesday was 42°C, what was the temperature on Wednesday?
- The average temperature on Monday, Tuesday, and Wednesday was 30C The Wednesday and Thursday are 31C. If the temperature on Thursday was 32C then what was the temperature on Monday?
- The increase in the rate of reaction due to the increase in temperature is due to?
- The average temperature for Wednesday, Thursday and Friday was 40°C. The average for Thursday, Friday and Saturday was 41° C. If temperature on Saturday was 42° C, what was the temperature on Wednesday?