At 3:00 AM, the temperature was 13°C below zero, but by noon it had risen to 32°C. Therefore, the average hourly increase in temperature was ______?

Answer: 5°C
Explanation

Initial temperature = -13°C

Final temperature = 32°C

Total temperature rise = 32 - (-13)

= 32 + 13

= 45°C

Time elapsed = 9 hours (from 3:00 AM to noon)

Average hourly increase = Total temperature rise / Time elapsed

= 45°C / 9 hours

= 5°C/hour

This question appeared in Past Papers (5 times)
PPSC 5 Years Past Papers Subject Wise (Solved with Details) (2 times)
PPSC PHP ASI Past Papers and Syllabus (1 times)
PPSC Punjab Police ASI Past Papers and Syllabus (1 times)
This question appeared in Subjects (1 times)
MATHS MCQS (1 times)

Install this app on your device for quick access right from your home screen.