For each integer n ≥ 1, the ∑100 = S(100) = 1 + 2 + 3 + ⋯ + 100 = 5050, then What is the value of S(200)?
Answer: 20100
Explanation
The formula for the sum of the first n natural numbers is:
S(n) = n(n + 1) / 2
Given S(100) = 5050, let's calculate S(200):
S(200) = 200(200 + 1) / 2
= 200 * 201 / 2
= 100 * 201
= 20100
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