If D = 1*10*100 the sum of the digits of D/8 + D/5 + D/4 + D/2 is?
If D = 1*10*100 the sum of the digits of D/8 + D/5 + D/4 + D/2 is?
Explanation
Let's calculate D:
D = 1 * 10 * 100 = 1000
Now, calculate each term:
D/8 = 1000 / 8 = 125
D/5 = 1000 / 5 = 200
D/4 = 1000 / 4 = 250
D/2 = 1000 / 2 = 500
Sum = 125 + 200 + 250 + 500 = 1075
The sum of the digits of 1075:
1 + 0 + 7 + 5 = 13