If D = 1*10*100 the sum of the digits of D/8 + D/5 + D/4 + D/2 is?

If D = 1*10*100 the sum of the digits of D/8 + D/5 + D/4 + D/2 is?

Explanation

Let's calculate D:

D = 1 * 10 * 100 = 1000

Now, calculate each term:

D/8 = 1000 / 8 = 125

D/5 = 1000 / 5 = 200

D/4 = 1000 / 4 = 250

D/2 = 1000 / 2 = 500

Sum = 125 + 200 + 250 + 500 = 1075

The sum of the digits of 1075:

1 + 0 + 7 + 5 = 13