Prove that √1-sin²θ/sinθ =?
Prove that √1-sin²θ/sinθ =?
Explanation
Let's simplify the expression:
√1-sin²θ/sinθ = √(cos²θ)/sinθ (since 1 - sin²θ = cos²θ)
= cosθ/sinθ
= cotθ
Let's simplify the expression:
√1-sin²θ/sinθ = √(cos²θ)/sinθ (since 1 - sin²θ = cos²θ)
= cosθ/sinθ
= cotθ