Explanation

Let the circumference of the circle = perimeter of the square = P  

- Circumference of circle = 2πr  

- Perimeter of square = 4a (a = side of square)  

So, 2πr = 4a ⇒ a = (πr)/2

- Area of circle = πr²  

- Area of square = a² = (πr/2)² = (π²r²)/4

Now compare:

πr² (circle) vs. (π²r²)/4 (square)  

Divide both sides:  

(πr²) / ((π²r²)/4) = 4/π > 1 ⇒ area of circle > area of square.