If one root of 2x2 + ax + 6 = 0 is 2 then the value of a is?
If one root of 2x2 + ax + 6 = 0 is 2 then the value of a is?
Explanation
One root = 2
Equation: 2x² + ax + 6 = 0
Using factor theorem, substitute x = 2:
2(2)² + a(2) + 6 = 0
⇒ 8 + 2a + 6 = 0
⇒ 2a + 14 = 0
⇒ 2a = -14
⇒ a = -7