Two numbers whose sum is 67 and difference is 3, the numbers are?

34 and 56

6 and 15

33 and 34

32 and 35

x + y = 67 ... (equation 1)

x - y = 3 ... (equation 2)

where x and y are the two numbers.

We can solve this system of equations by adding equation 1 and equation 2, which eliminates y:

2x = 70

Dividing both sides by 2 gives:

x = 35

Now that we have x, we can substitute it into equation 1 to find y:

35 + y = 67

Subtracting 35 from both sides gives:

y = 32

So, the two numbers are 35 and 32.