If one factor of the quadratic equation x^2 −3x−10=0 is (x−5), what is the other factor?

(x + 2)

(x - 2)

(x + 5)

(x - 10)

Given:
$x^2 - 3x - 10 = 0$

We are told that one factor is $(x - 5)$ .
So, we divide the quadratic by $(x - 5)$ to find the other factor:

Method:
Use factoring:

We want two numbers that multiply to $- 10$ and add to $-3$ .
These numbers are -5 and 2.

Thus,

$x^2 - 3x - 10 = (x - 5)(x + 2)$