The sum of the squares of two consecutive odd numbers is 394. The sum of the numbers is?
Answer: 28
Explanation
Let the two consecutive odd numbers be x and x + 2.
Given x² + (x + 2)² = 394:
x² + x² + 4x + 4 = 394
2x² + 4x - 390 = 0
x² + 2x - 195 = 0
(x + 15)(x - 13) = 0
x = -15 or x = 13
For x = 13, the numbers are 13 and 15.
13² + 15² = 169 + 225 = 394
The sum of the numbers is 13 + 15 = 28.
This question appeared in
Past Papers (6 times)
ETEA 25 Years Past Papers Subject Wise (Solved) (2 times)
ETEA Past Papers (1 times)
KPK Teacher Past Papers SST PST CT TT PET (2 times)
PST Past Papers (1 times)
This question appeared in
Subjects (1 times)
MATHS MCQS (1 times)
Related MCQs
- Find two consecutive numbers. the sum of the squares is 25
- Find two consecutive positive numbers such that the sum of their squares is 7 less than 120.
- The sum of the squares of two numbers is 97 and the squares of their difference is 25. The product of the two numbers is
- In a series of six consecutive even numbers, the sum of the second and sixth numbers is 24. What is the fourth number?
- The sum of three consecutive numbers is given what is the difference between the first and third numbers?
- The sum or two numbers is 37 and the difference of thier squares is 185, the difference of the two numbers is
- The difference between the two numbers is 5, and the difference between their squares is 65. The numbers are ______?
- The sum of squares of all numbers from 1 to 50 is?
- Which of the following sets is countable? cantor set , set of all real numbers , set of all rational numbers , set of irrational numbers
- The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is:
