Find lim x → 1^+ (2 + √x - 1) = ?
Find lim x → 1^+ (2 + √x - 1) = ?
Explanation
Given lim x → 1⁺ (2 + √x - 1)
As x approaches 1 from the right:
√x approaches √1 = 1
So, √x - 1 approaches 1 - 1 = 0
2 + 0 = 2
The limit is 2.
Given lim x → 1⁺ (2 + √x - 1)
As x approaches 1 from the right:
√x approaches √1 = 1
So, √x - 1 approaches 1 - 1 = 0
2 + 0 = 2
The limit is 2.