Find lim x → 1^+ (2 + √x - 1) = ?

Find lim x → 1^+ (2 + √x - 1) = ?

Explanation

Given lim x → 1⁺ (2 + √x - 1)

As x approaches 1 from the right:

√x approaches √1 = 1

So, √x - 1 approaches 1 - 1 = 0

2 + 0 = 2

The limit is 2.