The center of the circle 45x² + 45y² - 60x + 36y + 19 = 0?
The center of the circle 45x² + 45y² - 60x + 36y + 19 = 0?
Explanation
To find the center of the circle, rewrite the equation in standard form:
45x² - 60x + 45y² + 36y = -19
Divide by 45:
x² - (4/3)x + y² + (4/5)y = -19/45
Complete the square:
(x - 2/3)² + (y + 2/5)² = ...
The center is (2/3, -2/5).