In an isosceles triangle, the length of equal sides are 3x - 2y + 2 and x - y + 7. Find the value of x, if the sum of these sides is 12 cm?
In an isosceles triangle, the length of equal sides are 3x - 2y + 2 and x - y + 7. Find the value of x, if the sum of these sides is 12 cm?
Explanation
Given that the two sides of the isosceles triangle are equal:
3x - 2y + 2 = x - y + 7
This simplifies to:
2x - y = 5
The sum of the two equal sides is 12 cm:
(3x - 2y + 2) + (x - y + 7) = 12
This simplifies to:
4x - 3y = 3
Solving these two equations simultaneously, we find x = 6.