Find the value of a + b + c, when a² + b² + c² = 38 and ab + bc + ca = -1?
Find the value of a + b + c, when a² + b² + c² = 38 and ab + bc + ca = -1?
Explanation
Given:
a² + b² + c² = 38
ab + bc + ca = -1
Using the identity:
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
= 38 + 2(-1)
= 38 - 2
= 36
a + b + c = √36
= 6