If 1 - I, is a root of the equation x² + ax + b = 0, where a, b, ∈ R, then the value of a - b is?

-4

None of these

Given that 1 - i is a root of the equation x² + ax + b = 0, and the coefficients are real, the complex conjugate 1 + i must also be a root.

The sum of the roots = (1 - i) + (1 + i) = 2 = -a

So, a = -2

The product of the roots = (1 - i)(1 + i) = 1² - i² = 1 + 1 = 2 = b

So, b = 2

Now, a - b = -2 - 2 = -4