A 1000 kg vehicle is turning round a corner at 10 m/s as it travels along an arc of a circle, If the radius of the circular path is 10m, how large a force must be exerted by the pavement on the tyres to hold the vehicle in the circular path?
A 1000 kg vehicle is turning round a corner at 10 m/s as it travels along an arc of a circle, If the radius of the circular path is 10m, how large a force must be exerted by the pavement on the tyres to hold the vehicle in the circular path?
Explanation
To calculate the force exerted by the pavement on the tires, we can use the centripetal force formula:
Force (F) = (Mass (m) * Velocity squared (v^2)) / Radius (r)
Given:
Mass (m) = 1000 kg
Velocity (v) = 10 m/s
Radius (r) = 10 m
Calculate the centripetal force (F):
Using the formula, F = (m * v^2) / r, we can substitute the given values to find the force:
F = (1000 kg * (10 m/s)^2) / 10 m
F = 100,000 N / 1.0 x 10^4 N