If an object falls 27m and rebounds two-thirds, what is the total distance?

If an object falls 27m and rebounds two-thirds, what is the total distance?

Explanation

The object first falls 27m. On each rebound, it rises and falls two-thirds of the previous distance:

  1. Fall = 27m
  2. First rebound = 2/3×27=18m2/3 times 27 = 18m(up and down = 18+18=36m18 + 18 = 36m)
  3. Second rebound = 2/3×18=12m2/3 times 18 = 12m (up and down = 12+12=24m12 + 12 = 24m)
  4. Total distance = 27 + 36 + 24 = 105m.