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If an object falls 27m and rebounds two-thirds, what is the total distance?
If an object falls 27m and rebounds two-thirds, what is the total distance?
105m
135m
54m
120m
Fall = 27m
Explanation
The object first falls 27m. On each rebound, it rises and falls two-thirds of the previous distance:
Fall = 27m
First rebound =
2
/
3
×
27
=
18
m
2/3 times 27 = 18m
(up and down =
18
+
18
=
36
m
18 + 18 = 36m
)
Second rebound =
2
/
3
×
18
=
12
m
2/3 times 18 = 12m
(up and down =
12
+
12
=
24
m
12 + 12 = 24m
)
Total distance =
27 + 36 + 24 = 105m
27
+
36
+
24
=
105
m
.