The sum of three consecutive integers is 72. What is the smallest of three integers?
Answer: 23
Explanation
Let the three consecutive integers be x+1, and x+2.
According to the problem, their sum is 72:
x+(x+1)+(x+2)=72
Combine like terms:
3x+3=72
Subtract 3 from both sides:
3x=69
Divide by 3:
x=23
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