7x - 1 = 4x + 8
Add 1 to both sides:
7x = 4x + 9
Subtract 4x from both sides:
3x = 9
Divide both sides by 3:
x = 3
So, the value of x is 3.
x = 3+ √8
x = (3+√8)(3-√8) / (3-√8)
x = (9 -8) / (3-√8)
x = 1/ (3 -√8)
Or we can write 1/x = (3-√8)
Put the value and find out
x² +(1/x²) = x² + (1/x)²
So x² + 1/ x² = (3 +√8)² + (3 -√8)²
= 9+6√8+8 + 9–6√8+8
= 34.
Given polynomial: p(x) = x² - 4x + 3
Step 1: Factor the polynomial
p(x) = (x - 3)(x - 1)
Step 2: Find the zeros
Zeros are x = 3 and x = 1
Let's check each equation by plugging in a = -5:
(3/5)a + 19 = 16
→ (3/5)(-5) + 19 = -3 + 19 = 16 → True
So, the equation (3/5)a + 19 = 16 has a solution of a = -5
Let's calculate what needs to be added:
(7 + 2a - a² + 4a³) - (2a³ + a² - 3a - 1)
= 7 + 2a - a² + 4a³ - 2a³ - a² + 3a + 1
= 2a³ - 2a² + 5a + 8
Given:
(x + 1)(x - 5) = 0
This implies:
x + 1 = 0 or x - 5 = 0
Solving for x:
x = -1 or x = 5
Given x = 1:
x² + 1/x² = 1² + 1/1²
= 1 + 1
= 2
b^3/B^2
= b^(3-2)
= b^1 = 1
The correct answer is 1.
Let's factorize 2x^2 - 7x + 3. We need to find two numbers that multiply to 2 × 3 = 6 and add to -7. These numbers are -6 and -1.
So, 2x^2 - 7x + 3 = 2x^2 - 6x - x + 3
= 2x(x - 3) - 1(x - 3)
= (2x - 1)(x - 3)
Given the point (3, -4), where x = 3 (positive) and y = -4 (negative):
Step 1: Determine the quadrant
In the Cartesian coordinate system, Quadrant IV has positive x-coordinates and negative y-coordinates.