To expand the expression:
(√3 - √2)²
= (√3)² - 2(√3)(√2) + (√2)²
= 3 - 2√6 + 2
= 5 - 2√6
Let's solve the equation:
(3/2)x - 5/2 = 1/2
Add 5/2 to both sides:
(3/2)x = 1/2 + 5/2
(3/2)x = 6/2
(3/2)x = 3
Multiply both sides by 2/3:
x = 3 × (2/3)
x = 2
Let's solve for x:
x/2 + x/3 + x/6 = 10
To add these fractions, find a common denominator (6):
3x/6 + 2x/6 + x/6 = 10
6x/6 = 10
x = 10
Let's simplify the expression:
√25^(3x) = √(5²)^(3x) = √(5^(6x)) = 5^(3x)
Now, divide by 5^(6x-2):
5^(3x) / 5^(6x-2) = 5^(3x - 6x + 2) = 5^(-3x + 2)
For this to equal one of the given options (5, 10, 15), let's see if -3x + 2 = 1 (for 5¹ = 5):
-3x + 2 = 1
-3x = -1
x = 1/3
Then, 5^(-3(1/3) + 2) = 5¹ = 5
The expression √8-√2 simplifies to √2.
A group generated by one of its elements is called a cyclic group.
This means that the group can be generated by repeatedly applying the group operation to a single element, called the generator.
In other words, all elements of the group can be expressed as powers of the generator.
If AB = BA, it means the matrices commute under multiplication.
So, they are called multiplicative commutative (or simply commutative) matrices.
Given 12 = PQ, we can write P = 12/Q.
For proportion:
4 : Q = P : 3
4/ Q = P / 3
4 × 3 = P × Q
12 = PQ
This matches the given equation.
The answer is 4 : q = p : 3.
a + b = 2 ... (1)
a - b = 2 ... (2)
Adding (1) and (2):
2a = 4
a = 2
Put a = 2 in (1):
2 + b = 2
b = 0
Now, a² + b² = (2)² + (0)² = 4 + 0 = 4.